Science, asked by jyotishyadav5001, 4 months ago

3. A position dependent force, F = 7-2x+3x2-N acts on a small body of mass 1 point
2kg and displaces it from x = 0 to x = 5m. The work done in joules is​

Answers

Answered by scientist1234567
2

Answer:

Given that,

Force F=7−2x+3x

2

We know that,

F=

dx

dw

dw=Fdx

Now, the work done is

∫dw=

0

5

F⋅dx

∫dw=

0

5

(7−2x+3x

2

)dx

W=[7x−

2

2x

2

+

3

3x

3

]

0

5

W=35−25+125

W=135J

Hence, the work done is 135 J

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