Question

3) A projectile is projected at an angle of 60° with horizontal & with a
velocity of 30 m/s. The velocity of the projectile at the highest point of its
trajectory is?
Oo
O 15 m/s
O 20 m
O 30 m/s
20 m/s​

Answer 1

Answer:

15 m/s

Explanation:

at the highest point vertical velocity of the object will become zero and because of this the object will only have forward velocity which we can directly say would be => 30 cos 60 = 30 * 1/2 = 15m/s

Answer 2

Answer:

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Explanation:

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