Question

3.
A quadratic polynomial whose one zero is 6 and sum of the
zeroes is 0 is
a) x^2 - 6x+2 b) x^2-6
c) x²-3
d) x^2-36​

Answer 1

Answer:

let alpha =6

alpha+beta=0

beta=-alpha

beta=-6

Sum of zeros=0

product of zeros=6*-6=-36

quadratic equation=

$k( {x}^{2} - (sum \:of \: zeros)x + (product \: of \: zeros))$

$k( {x}^{2} - 0.x - 36)$

$k( {x}^{2} - 36)$

answer is d.

Answer 2

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