3. A ray of light is deviated through an angle of 600 by a plane mirror. Find (i) incident angle (ii) reflected angle (iii) angle between the mirror and the direction of incident ray.
Answers
Answered by
1
Answer:
given : ∠i+∠r=80
0
Solution: ∠i+∠r=80
0
→(1)
and for a plane mirror
∠i=∠r →(2)
then from (1) and (2)
2∠i=80
0
∠i=40
0
Hence
Hence from the figure θ+40
0
=90
0
Hence θ=50
0
Answered by
0
Answer:
Correct option is
D
120
o
Since angle of incident =angle of reflection
Hence r=30
0
And here angle of deviation,
δ=180
0
−(i+r)
δ=120
0
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