Question

3. A rectangular field has 80 m length and 48 m breadth. Three roads, each of width 2 m
pass through the field such that two roads are parallel to the breadth and the third road
parallel to the length. Find the area covered by the three roads.​

Answer 1

$\: \: \boxed{\boxed{\bf{\mapsto \: \: \: Question}}}$

A rectangular field has 80 m length and 48 m breadth. Three roads, each of width 2 m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length. Find the area covered by the three roads.

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$\: \: \boxed{\boxed{\bf{\mapsto \: \: \: firstly \: let's \: understand \: the \:question}}}$

According to the question, it is given that A rectangular field has

• 80 m length

• 48 m breadth

• width of each road 2 m

pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.

and we need to find the area covered by the three roads.

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Given,

» Length of a rectangular field = 80 m

» Breadth of a rectangular field = 48 m

» Width of the three roads = 2m

» the third road parallel to the length

[ You can see the figure in the attachment ]

To find ,

» the area covered by the three roads

~ Let's solve it ,

total area covered by roads -

⌬ area of two road parallel to the breadth + area of road parallel to the length - area of common part ( in both roads )

• Area of two road = 2 × ( 48 × 2 )

• Area of road parallel at length = 80 × 2

• Area of common part = ( 2 × 2 ) + ( 2 × 2 )

~ By putting all the values ,

$\sf⌬ \: \: \: 2 \times (48 \times 2) + (80 \times 2) -(2 \times 2 \times 2)$

$\sf⌬ \: \: \: 2 \times96 + 160 - 8$

$\sf⌬ \: \: \: 192 + 160 - 8$

$\sf⌬ \: \: \: {344m}^{2}$

$\: \: \boxed{\boxed{\bf{\mapsto \: \: \: Hence, \: total \: area \: covered \: by \: roads is \: \: \underline{\underline{344m}}}}}$

Answer 2

Answer:

We can see that the length and breadth of these common areas is 2 m. The area covered by the three roads is 344 m. square