Question

3. A room is 10 m long and 6 m broad. Find the cost of carpeting its floor when the rate of the carpet is 7.00 per square metre.

4. A courtyard 20 m long and 15 m broad is to be paved with brick of 25 cm and breadth 12 cm. Find the number of bricks required.​

Answer 1

Answer:

3) As, the area of the floor = length x breadth = 16 x 13.5 = 216 m2 And, the width of the carpet = 75 m So, the length of the carpet required = Area of the floor/Width of the carpet = 216/75 = 2.88 m Now, the cost of the carpet required = 2.88 x 60 = 172.80 Hence, the cost of covering the floor with carpet is 172.80. Read more on Sarthaks.com - https://www.sarthaks.com/165724/room-long-and-broad-find-the-cost-of-covering-its-floor-with-75-wide-carpet-at-rs-60-per-metre

Answer 2

$Question→3$

A room is 10 m long and 6 m broad. Find the cost of carpeting its floor when the rate of the carpet is 7.00 per square metre.

$*Answer:-$

Length of the room = 10 meters.

Breadth of the room = 6 meters.

Area of the room = (10×6) meter^2 = 60 meter^2.

Area of carpet used = Area of the room = 60 meter^2.

》Length of carpet × Width of carpet = 60 meter^2.

》Length of carpet × 0.60 meter = 60 meter^2.

》Length of carpet = (60/0.60) meter = 100 meter.

Now,

Cost of carpet used = Rs. (100 × 2.37) = Rs. 237.

Thus, Cost of carpeting the floor = Rs. 237.

$Question => 4$

A courtyard 20 m long and 15 m broad is to be paved with brick of 25 cm and breadth 12 cm. Find the number of bricks required.

$answer = >$

Required no. of bricks = area of courtyard/ area of bricks

→ 20 × 15m²/ 0.25 × 0.12m²

→ 300/0.03

→ 300 × 100/3

→ 30,000/3

→10,000 bricks