Question

3) A solid body floating in water has 1/6th of the
volume above surface. what fraction of its
volume will project upwards. if its floats
in a liquid of specific gravity 1.2.
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Answer 1

Answer:

Explanation:

Using law of flotation  

Vwater  displaced = V-V/6 = 5V/6  

Vsolid xPSolidxg = v water displaced x p water x g  

V x P solid x g = (5V/6) x p water x g  

Psolid = (5000/6) kg/m3  

When liquid of 1020 kg/m3 is used  

V solid x P solid x g = V liquid displaced x p liquid x g  

V (5000/6) = V liquid displaced x 1020  

V liquid displaced = .81V  

So .81V is inside liquid  

V- 0.81V = 0.19V will project upward