Question

3. A spring of force constant 800 N/m has an extension of 8 cm. The work done in extending it from 8 cm to 16 cm is 1) 16 J 2) 7.68 J 3) 32 J 4) 24 J
plz solve this with explanation​

Answer 1

HEY YOUR ANSWER IS READY

Step-by-step explanation:

The work done is stored as elastic potential energy in the spring. 

It is given by

W=21×k(x₂²−x₁²)

 x₁=5cm

 x₂=15cm

k=800mN=100800cmN=8cmN

 W=21×8(15²−5²)=21×8(225−25)

 =21×8×200=800cmN 

W=800cmN=8mN=8J

I HOPE IT HELP YOU