Question

3. A square loop of side 6 cm carries a current of 30 A. Calculate the magnitude of magnetic field
B at a point Plying on the axis of the loop and a distance 17 cm from centre of the loop,​

Answer 1

Answer:

Explanation:

r=  

9+7

​  

=4cm

   B=  

4π

μ  

o

​  

 

​  

 

r

i

​  

(2sinα)

      =(10  

−7

)(  

4×10  

−2

 

30

​  

)(2×  

5

3

​  

)

      =9.0×10  

−5

T

Net field = 4Bsinθ

              = 4×9.0×10  

−5

×  

4

3

​  

 

              = 2.7×10  

−4

T