Question

3 a square minus a b - 14 b square

Answer 1

Answer:

$= > 3 {a}^{2} - ab - 14 {b}^{2} \\ = > 3 {a}^{2} + 6ab - 7ab - 14 {b}^{2} \\ = > 3a(a + 2b) - 7b(a + 2b) \\ = > (3a - 7b)(a + 2b)$

Answer 2

$\huge\underline\mathtt{Answer:}$

$\sf{3 {a}^{2} - ab - 14b}$

$\sf{3 {a}^{2} + 6ab - 7ab - 14b }$

$\sf{ = 3a(a + 2b) - 7b(a + 2b)}$

$\sf{ = (a + 2b)(3a - 7b)}$