Physics, asked by satyanarayanaakaboti, 6 months ago

3. A Stone dropped from top of a well reaches the surface of water in 2 seconds, find the
velocity of stone while it touches the surface of water and what is the depth of the water
surface from top of well (g=10m/s2) (Using V=U+at, S=Ut+1/2 at square) ​

Answers

Answered by sahilshejwal4
2

Answer:

correct answer is 2.

Explanation:

A stone dropped from top of a well reaches the surface of ... from top of well(g =10m/S2)(using V=U+at,S=Ut+1/2 at2). 2.

34 votes

Answered by agrahariprakhar2
5

Answer:

Formula of velocity = V=U+GT

V=0+10×2

V=20M/S

Formula of distance is H =UT+1/2GT^2

H=0×2+1/2×10×4

H=20M

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