Question

3. A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force

on the stone during its upward motion?

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Answer 1

Answer: Downwards with a magnitude of my = 0.05 * 10 = 0.5N.

Explanation: While moving my upwards only gravity acts on it. Therefore the net force on it is "mg" downwards i.e towards Earth unless

you account the air resistance.

Answer 2

Answer:

0.49 N [ vertically downward ]

Explanation:

Given :

Mass of stone = 0.05 kg

We are asked to find net force and direction .

Force acting on stone = Mass times acceleration due to gravity  .

i.e. F_net = m g

Putting values here we get :

F_net = 0.05 × 9.8 N

F_net = 0.49 N

Direction of force is vertically downward .

Therefore we get required answer.