Physics, asked by Ecommerce6293, 10 months ago

3. A stone placed at bottom of a water tank appears to be raised by 80 cm. If the RI of water is 4/3, find the actual depth of the water tank.

Answers

Answered by Anonymous
46

  \large{\red{ \bf{ \underline {\underline{Answer}}}}} \\  \\  \purple{ \sf{\mapsto The \: actual \: depth \: of \: water \: tank = 320 \: cm}} \\  \\   \mathrm{\green{ \underline{Given}}} \\  \\  \sf{ \rightsquigarrow Appears \: raised = 80 \: cm} \\  \\ \sf{ \rightsquigarrow Reflection \: index \: (RI) =  \frac{ \: 4 \: }{  \: 3 \: } }\\ \\ \mathrm  {\blue{ \underline{ To \: Find}}} \\  \\  \sf{ \rightsquigarrow Actual \: depth\:of\:water\:tank\:=\:?}

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According To Given Question

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 \sf{Let \: the \: real \: depth \:of \: tank \: be \: x} \\  \\  \sf{Apparent \:  thickness =(x-80) \:  cm} \\  \\  \sf{:  \implies  \mu  =  \frac{Real  \: depth}{Apparent \:  thickness} } \\  \\  \sf{ : \implies  \frac{4}{3}  =  \frac{x}{x - 80} } \\  \\  \sf{ : \implies 4x - 320 = 3x} \\  \\  \sf{ : \implies 4x - 3x = 320} \\  \\  \sf{ \purple{ : \implies  \underline{ \boxed{ \sf{x = 320 \: cm}}}}}

\sf{\purple{\therefore\:Hence, \:the\:actual\:depth\:of\: water \:tank=320\:cm}}

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