3. A string of negligible mass going over a
clamped pulley of mass m supports a block of
mass Mas shown in the figure. The force on the
pulley by the clamp is given by
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Answer:
Force on pulley by the clamp = resultant of T = (M+m)g and mg acting along horizontal and vertical directions respectively
F=√[(M+m)g]2+(mg)2
=[(M+m)2+m2]g
Explanation:
Note : in every term 2 is an exponent
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