Question

3.
A student walks at a speed of 5 km/h starting from his house and reaches his office 6 minutes
later. Next day he increases his speed by 1 km/h and reaches office 6 minutes early. How far is
the office from his house?

Answer 1

first you need to convert minutes into hours 6 minutes will be 0.1 hours.

case i

S=5×t+0.1

case ii

S=6×t-0.1

5×t+0.1=6×t-0.1

5t-6t=-0.5-0.6

t=1.1 hours

S=5×1.1

S=5.5 KM