3. A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at
a point Q so that OQ = 12 cm. Length PQ is :
(A) 12 cm
(B) 13 cm
(C) 8.5 cm
(D) √119 cm
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Explanation:
In the above figure, the line that is drawn from the centre of the given circle to the tangent PQ is perpendicular to PQ.
And so, OP ⊥ PQ
Using Pythagoras theorem in triangle ΔOPQ we get,
OQ² = OP² +PQ²
↪(12)² = 5² + PQ²
↪PQ² = 144 - 25
↪PQ² = 119
↪PQ = √119 cm
So, option D i.e. √119 cm is the length of PQ.
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