3) A team of 7 persons (2 men and 5 women) should be constructed from a group of 8 women and 4 men. In how many ways is this possible?
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Answer:
336 ways
Explanation:
Total = 7
2 men out of 4 and 5 women out of 8
4c2 * 8c5
nCr = n!/[r! (n – r)!
Substituting n = 4 and r = 2 in the above formula,
4C2 = 4!/ [2! (4 – 2)!]
= 4!/ (2! 2!)
= (4 × 3 × 2 × 1)/ (2 × 1 × 2 × 1)
= 6
Therefore, the value of 4C2 is 6
likewise 8c5 value is 56
6*56 = 336 ways
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