Question

3. A telephone wire 125 m long and 1 mm in
radius is stretched to a length 125.25 m
when a force of 800 N is applied. What is
the value of Young's modulus for material​

Answer 1

Young’s Modulus will be 6.36 × 10^10 Pa

Explanation:

Force = F = 800N  

Area = A = πr^2 = π(1m)^2 = 3.14 × 10^(-6) m^2

Initial length = L1 = 125 m

Final length = L2 = 125.5 m

Change in length = ∆L = L2 - L1 = 0.5m

Now. We will use formula for the young’s modulus

Y = (F/A) / (∆L/L1 )

By putting values we get,

Y =  6.36 × 10^10 Pa

Answer 2

Answer:

1.273×10^11 N/m^2

Explanation:

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