______________________________________________________________ 3) A tent is of the shape of a right circular cylinder up to height 3 m and then becomes the right circular cone with a maximum height of 13.5 m above the ground. Calculate the cost of painting the inner side of the tent at the rate of $2 per sq. m., if the radius of the base is 14 m.
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I don't know for this answer, sorry
Priyanshu1122:
the ans is $7236
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Height of the conical part of the tent=total height - height of the cylindrical part of the tent
=13.5-3=10.5m
Required area = curved surface area of cylinder + curved surface area of cone
=2πrh+πrl
Curved surface area of cylinders=2πrh
=2×22/7×14×3
=263.89m^2
Curved surface area of cone =πrl
l=√r^2+h^2
=17.5m
CSA of cone=22/7×14×17.5
=769.69m^2
Total area to be painted
= 263.89+769.69
=1033.58m^2
Total cost =2×1033.58
=$2067.16
Therefore, cost of painting the inner sides of the tent is $2067.16
Thank You
=13.5-3=10.5m
Required area = curved surface area of cylinder + curved surface area of cone
=2πrh+πrl
Curved surface area of cylinders=2πrh
=2×22/7×14×3
=263.89m^2
Curved surface area of cone =πrl
l=√r^2+h^2
=17.5m
CSA of cone=22/7×14×17.5
=769.69m^2
Total area to be painted
= 263.89+769.69
=1033.58m^2
Total cost =2×1033.58
=$2067.16
Therefore, cost of painting the inner sides of the tent is $2067.16
Thank You
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