Question

[3] (a) The sum of squares of two numbers is 13 and their product is 6. Find i. The sum of two numbers. ii. The difference between them.​

Answer 1

Answer:

$x - y = + 1$

Step-by-step explanation:

let x and y be two numbers then

${x}^{2} + {y}^{2} = 13 \: and \: xy = 6 \\( i) \: {(x} + y {)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ = 13 + 2 \times 6 \\ = 13 + 12 \\ = 25 \\ x - y = + \sqrt{25 \: } = + 5 \\( ii) \:(x + y {)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ = 13 - 12 \\ = 1 \\ = x - y = + 1$