Question

3. A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same
The total height of the toy is 15.5 cm. Find the total surface area of the toy.​

Answer 1

$\textbf{ Solution:}$

Area of Cone of toy :

$\pi \: rl \: = \frac{22}{7} \times 3.5 \times 3.5 \times l$

Now we need to slant height of the toy So : 15.5 -3.5.=12.5

$l = \sqrt ({r})^{2} + ({h}^{2} ) \\ = \sqrt{ ({3.5})^{2} } + ( {12}^{2} ) \\ = \sqrt{12.25 + 144} \\ = \sqrt{156.25 } = 12.5$

Now total surface area of toy :

$= 2\pi \: r^{2} + \pi \: r \: l \: \\ = 2 \times \frac{22}{7} \times 3.5 \times 3.5 + \frac{22}{7} \times 3.5 \times 12.5 \\ \\ = 214.5 {cm}^{2}$

Answer 2

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