3. A train leaves Station A at 9:00 a.m. and reaches Station B at 2:00
p.m. The total time for stoppages was 1 hour. If the distance
between the stations is 240 km, find the average speed. Also, find
the train's speed.
Answers
Given: Total time to reach from Station A to Station B
is 5 hrs.
Stoppage Time is 1 hr.
Distance between the two Stations is 240 Km.
To find: a) Average Speed
b) Train's Speed
Solution: a) average Speed is defined as :
" Total distance covered divided by total time taken to cover that distance".
Therefore, average speed = 240/5 = 48 Km/hr
b) Train's Speed = Total Distance covered by train divided by time for which the train was moving.
Hence, Train's speed = 240/4 = 60 Km/hr
Therefore average speed is 48 km/hr and train's speed is 60 km/hr.
Answer:
Solution: a) average Speed is defined
as:
"Total distance covered divided by total time taken to cover that distance".
Therefore, average speed = 240/5 = 48
Km / h * r
b) Train's Speed = Total Distance covered by train divided by time for which the train was moving.
Hence, Train's speed = 240/4 = 60Km / h * r
Therefore average speed is 48km / h * r and train's speed is 60km / hrs.