Question

3. A train starting from a rallway
station and moving with uniform
acceleration attains a speed
40 kmh in 10 minutes. Find its
occeleration​

Answer 1

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Answer 2

Answer:

t=10 min=10×60=600s

Initial speed of train is given as: u=0 ms−1

Final speed of train is given as: v=40 km h−1=360040×1000=11.1 ms−1

Now acceleration is given by the relation:

a=tv−u=60011.1−0=0.0185 ms−2

Explanation:

As the train started from a railway station, so initial velocity of train, u = 0

Final velocity of train, v = 40 kmph

Final velocity, v = 40 × 5/18 = 11.11 m/s

Assuming uniform acceleration of ‘a’ m/second square

Time taken by train to get it's final velocity, t = 10 minutes = 600 seconds

Using first equation of motion,

V = u + at

11.11 = 0 + a×600

a = 11.11/600 = 0.0185 m/second square.

So, required acceleration , a = 0.0185 m/second square.