Question

3) A Train starting from rest attains a speed of 12km/HR in 5min Find the acceration and the distance traveled​

Answer 1

Explanation:

initial velocity,u=0

final velocity,v=12km/hr

time,t=5 min=5/60 hours

now v=u+at

12=0+a×5/60

12×60/5=a

a=144km/hr2

now

${v}^{2} - {u}^{2} = 2as$

12×12-0=2×144×s

1/2=s or s=0.5km