3. A train travels 96 km in 40 minutes from station A to station B. If it passes through a station C, 30 minutes
after leaving A, what is the distance between station B and station C?
Answers
Answer:
Distance between A B = 108 Kms.
Time taken = 45 mins = 45/60 = 3/4 Hrs = 0.75 Hrs.
So the speed of the train = 108/3/4 = 108 x 4/3 = 144 Kms / Hr.
The distance between A C will be = Speed x Time
= 144 x 40/60 = 144 X 2/3 = 96 Kms.
Since the distance between A B is 108 Kms the distance between A C is 96 Kms, then the distance between B C = 108 - 96 = 12 Kms.
Ans: 12 Kms.
OR
We can solve the problem in a different way:
Distance between A B = 108 Kms.
Time taken = 45 mins = 45/60 = 3/4 Hrs = 0.75 Hrs.
So the speed of the train = 108/3/4 = 108 x 4/3 = 144 Kms / Hr.
Time taken to travel from A to B = 45 mins.
Time taken to travel from A to C = 40 mins.
So the train travels from C to B in 45 - 40 = 5 mins.
So the distance travelled by the train in 5 mins = Speed X Time = 144 x 5/60 = 12 Kms.
Ans: 12 Kms.