Question

3. A train travels at a speed of 60km/h for 0.5h, 24km/h for the next 0.25h and then

at 72km/h for the next 0.75h. Calculate the total distance covered by the train

and its average speed?​

Answer 1

Given :-

• A train travels at a speed of 60km/h for 0.5h, 24km/h for the next 0.25h and then at 72km/h for the next 0.75h

To find :-

• Distance covered
• Average speed

Solution :-

In 1st case

• Speed = 60km/h
• Time (t1) = 0.5h
• Distance = ?

As we know that

→ Distance = speed × time

Let the distance be D1

→ D1 = 60 × 0.5

→ D1 = 30 km

In 2nd case

• Speed = 24km/h
• Time (t2) = 0.25 h
• Distance = ?

Let the distance be D2

→ D2 = 24 × 0.25

→ D2 = 6km

In 3rd case

• Speed = 72km/h
• Time (t3)= 0.75h
• Distance = ?

Let the distance be D3

→ D3 = 72 × 0.75

→ D3 = 54km

Now, average speed

→ Total distance travelled/total time taken

→ D1 + D2 + D3/t1 + t2 + t3

→ 30 + 6 + 54/0.5 + 0.25 + 0.75

→ 90/1.5

→ 60 km/h

Hence,

• Total distance travelled = 90km
• Average speed = 60km/h

Answer 2

Hey dear!!!

Answer will be 60 km/h

The solution is in the upper attachment..

Hope it's help you dear