Question

3) A tree broke at height 7m from the ground and touches the ground at
a distance of 24 cm from the base of the tree. Find original height of
the tree.

Answer 1

Answer:

let the broken part of tree be x

then total height of tree=7+x

since it form a right angled triangle with base 24m and height 7m and hypotenuse be x

then by using Pythagoras theorem

(hypotenuse)^2=(base)^2+(height)^2

x^2=24^2+7^2

x^2=576+49

x^2=625

x=25

therefore height of tree =x+7=25+7=31

Step-by-step explanation: PLS MARK ME AS BRAINLIST

Answer 2

Answer:

32 m

Step-by-step explanation:

A

|

|

| 7m

|

|___________________________

B 24 m C

The total length of tree is L,

but it has fallen from A,

So length of tree = AB + AC.

Here A,B,C form a right angled traingle,

So, AC²= AB²+BC²

AC² = 7²+24² = 625 = 25²

So, AC = 25m

The total length of the tree = AB + AC

= 7m + 25m

= 32m

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