Question

3.A triangle has an area of 11.6 sq.cm. If the height is 2.9 cm. Find its base
(2 Points)

Answer 1

Step-by-step explanation:

Area of triangle=1/2* b*h

11.6 = 1/2*2.9*b

11.6*2/2.9 = b

8 cm = b

Answer 2

Correct Question

• A triangle has an area of 11.6 cm² . If the height is 2.9 cm. Find its base?

Given:

• Area (a) = 11.6 cm²
• Height (h) = 2.9 cm

To Find:

• Base (b) of the Triangle?

Solution:

Let the base of the triangle be x

$\\ \circ \: {\underline{\boxed{\tt{ Area_{(Triangle)} = \dfrac{1}{2} \times Base_{(b)} \times Height_{(h)} }}}}$

After substituting values,

$\\ \colon\implies{\tt{ a = \dfrac{1}{2} \times b \times h }} \\ \\ \\ \colon\implies{\tt{ 11.6 = \dfrac{1}{2} \times x \times 2.9 }} \\ \\ \\ \colon\implies{\tt{ \dfrac{ \cancel{ 11.6 } \times 2}{ \cancel{2.9} } = x }} \\ \\ \\ \colon\implies{\tt{ x = 4 \times 2 }} \\ \\ \\ \colon\implies{\boxed{\mathfrak\purple{ x = 8 \ cm }}}$

Hence,

• The Base of the Triangle is 8 cm.

More to Know:

$\\ \circ \: {\boxed{\tt{ \green{ Perimeter_{( \Delta )} } = a + b + c }}} \\ \\ \circ \: {\boxed{\tt{ \purple{ Area _{( \Delta )} } = \sqrt{ s(s-a)(s-b)(s-c) } }}}$