Question

3
A trolley, while going down an
inclined plane, has an
acceleration of 2 cm s*2. What will
be its velocity 3 s after the start?
​

Answer 1

Solution,

Here, we have

Initial velocity of the trolley, u = 0 (As starts from rest)

Acceleration of the trolley, a = 0.02 m/s²

Time taken by the trolley, t = 3 seconds

To Find,

Final velocity of the trolley, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of the trolley is 0.06 m/s.

Answer 2

Answer:

Given in question

Acceleration (a)=2cm/s^2

Time=3s

acceleration unit is m/s^2

A=2/100=0.02 m)s^2

velocity (v)= u+at

v=0+0.02×3

v=0.06 m/s^2

So 0.06 m/s^2 is the velocity