Question

3. A vertical pole stands on the level ground. From
a point on the ground, 25 m away from the foot
of the pole, the angle of elevation of its top is found
to be 60° Find the height of the pole.
​

Answer 1

Answer:

$\huge\mathfrak{\red{Answer:-}}$

$\large\fbox{\purple{25√3 m}}$

Step-by-step explanation:

$\huge\underline\mathcal{\red{Question:-}}$

$\implies$ A vertical pole stands on the level ground. From a point on the ground, 25m away from the foot of the pole, the angle of elevation of its top is found to be 60° Find the height of the pole.

$\huge\underline\mathcal{\green{Hint:-}}$

• Here, the concept of introduction to trigonometry is used.

• We will first draw the figure according to the given information, then we will use the trigonometric ratios to solve the respective problem.

$\huge\underline\mathcal{\blue{Solution:-}}$

Given, distance between the foot of the pole and the point, BC = 25m

Angle of elevation, $\theta$ = 60°

To find:-

The height of the tower, AB

We know that since the pole is standing vertically therefore, it forms an angle of 90° with the ground.

In right ∆ ABC;

We will use the trigonometric ratio tan 60° (because perpendicular/base= tan$\theta$ )

$\therefore$ we have

$\frac{AB}{BC} = \tan(60)$

$\frac{AB}{25} = \sqrt{3}$

Since, tan 60° = √3

$AB = 25 \sqrt{3} \: m$

Hence, the height of the pole is 25√3 m.

_____________________________________________

$\tiny\mathfrak{\red{@MissTranquil}}$

Answer 2

Step-by-step explanation:

3. A vertical pole stands on the level ground. From

a point on the ground, 25 m away from the foot

of the pole, the angle of elevation of its top is found

to be 60° Find the height of the pole.