Question

3. A vessel contains water up to a height of 1.5 m. Taking
the density of water 103 kg m-?, acceleration due to
gravity 9.8 m s-2 and area of base of vessel 100 cm²,
calculate : (a) the pressure and (b) the thrust, at the
base of vessel. Ans. (a) 1.47 x 104 N m-2 (b) 147 N​

Answer 1

Answer:

Option(B)

Explanation:

We know that,

P = ρgh

⇒ P = 10³ * 9.8 * 1.5

⇒ P = 1.47 * 10⁴ Nm²

Now,

Upthrust = Force Exterted = Pressure/Times area

⇒ Upthrust = 1.47 * 10⁴ * 100 * 10⁻⁴

                  = 147 N

Therefore,

Upthrust = 147 N

Hope it helps!

Answer 2

Answer:

(a) 1.47 × 10⁴ Pa

(b) 147 N

Explanation:

Pressure = $\frac{Force}{Area}$

Pressure = $\frac{mg}{A}$ = $\frac{density * volume * g}{Area}$ = $\frac{1000*1.5*0.01* 9.8}{0.01}$ = 14700 Pascal

Thrust = mg = 147 N