Question

3). A wall 4.8 m long and 3.1 m high is
covered with rectangular tiles of size
22 cm by 10 cm. Find the total cost of
the tiles at the rate of Rs 1.50 per tile.
​

Answer 1

Answer:

L=4.8m=480cm. , B=3.1m=310cm

l=22cm. ,. b=10cm

Total No. =(Area of wall)/(Area of each tile)

of tiles. ={(L×B)}/{(l×b)}

=(480cm×310cm)/(22cm×10cm)

=(148800cm^2)/(220cm^2)

=(7440/11) tiles

Total Cost of tiles=1.50®×(7440/11)

=3®×(3720/11)=(11160/11)

=1014.5454®

Answer 2

ɢɪᴠᴇɴ :

• length of the wall is 4.84 m
• breadth of the wall is 3.1 m
• size of tiles is 22 cm by 10 cm
• cost of 1 tile is ₹1.50

ᴛᴏ ғɪɴᴅ :

• the total cost of all tiles

sᴏʟᴜᴛɪᴏɴ :

Area of wall = length x height

= 4.84 x 3.1

= 15.004 m²

= 15.004 x 10,000

= 150040 cm²

Area of one tile = 22 x 10

= 220 cm²

∴ Number of tiles = $\sf{\frac{( Area\: of \:the\: wall )}{( area\: of \:1 \:tile)}}$

= $\sf{\frac{150040}{220}}$

= 682 tiles

Cost of 1 tile = ₹ 1.50

∴ Cost of 682 tiles = 682 × 1.50 = ₹1023