Physics, asked by stephanielomocso, 11 months ago

3. A wire 10m long of area of cross section 1.22cm2 elongates by 1.5 cm when 4.5 kg is suspended from it. Find the (i) stress (ii) strain and (iii) young's modulus of the wire. (g = 9.8m s-2)

Answers

Answered by maniyachawla12
0

Answer: I think this can help you

Explanation:

Given, length of wire, l = 2m

cross sectional area , A = 10^-4 m²

Load , F = 102kgwt = 102 × 9.8 N

extension of wire, ∆l = 0.1cm = 0.001m

Longitudinal stress = F/A

= 102 × 9.8/(10^-4)

= 999.6 × 10^4 ≈ 1 × 10^7 N/m²

Longitudinal strain. = extension of wire/original length of wire = ∆l/l

= 10^-3/2 = 5 × 10^-4

we know, Young's modulus = longitudinal stress/longitudinal strain

= 1 × 10^7/5 × 10^-4

= 20 × 10^9 N/m²

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