Question

3. A wire when bent in the form of a square en-
closes an area = 576 cm2. Find the largest area
enclosed by the same wire when bent to form:
(i) an equilateral triangle.
(ii) a rectangle whose adjacent sides differ by
4 cm.
plz say this line by line exaplaintion I want plzz​

Answer 1

Answer:

Area of a square=side

2

⇒576=side

2

⇒ Side=24m

Length of wire= Perimeter of square=4×Side

=4×24=96m

(i)Perimeter of equilateral triangle=Length of wire

3×Side of equilateral triangle=96

Side=

3

96

=32m

Area of an equilateral triangle

4

3

(side)

2

=

4

3

(32)

2

=

4

3

×1024

=256

3

m

2

(ii)Perimeter of rectangle=Length of wire

2(l+b)=96

⇒2(36+b)=96

⇒36+b=48

⇒b=48−36=12m

Area of rectanglel×b=36×12=432m

2