3. (a) Write a pair of negative Integers whose difference gives 5:
(b) Write a negative Integer and a positive integer whose sum is -2:
and
(c) Write a negative Integer and a positive integer whose difference is -3: and
(d) Write five pairs of integers (a, b) such that a + b = -3, one such pair is (6.-2):
Answers
Answer:
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Answer:
(a) 1st number = x
2nd number = (take any random number) 2
x - 2 = 5
x = 5 + 2
x = 7
Hence, 7 - 2 = 5
(b) 1st number = x
2nd number = 5
x + 5 = - 2
x = - 2 - 5
x = -7
Hence, - 7 + 5 = - 2
(c) 1st number = a
2nd number = 7
a + 7 = - 3
a = - 3 - 7
a = - 10
Hence 1st pair = - 10 + 7 = - 3
Use the same method to find out the other four or just add 1.
Eg. (- 10 + 1) + (7 + 1) = - 3
- 11 + 8 = - 3 (2nd pair)
3rd pair = -12 + 9 = - 3
4th pair = - 13 + 10 = - 3
5th pair = - 14 + 11 = - 3
Hope it helps