Question

هييه
3) a2 +b²=41 ab=4 find a-b and a+b
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Answer 1

${\fbox{\boxed {\huge{\rm{\red{Answer!!}}}}}}$

${\boxed{({a + b})^{2} = {a}^{2} + b ^{2} + 2ab}}$

${\implies{(a + b) = \sqrt{41 + 8} = + - 7}}$

${\implies{\rm{({a + b})^{2} = - 4ab = ({a - b})^{2} }}}$

${\implies{ \rm{ \sqrt{49 }- 4(4) = (a - b)}}}$

${\huge{\green{\rm{bebrainly}}}}$

Answer 2

Step-by-step explanation:

$\sf {a}^{2} + {b}^{2} = 41 \:and\: ab = 4 \\ \\ \sf {( a + b )}^{2} = {a}^{2} + 2ab + {b}^{2} \\ \\ \sf {(a + b )}^{2} = 41 + 8 \\ \\ \sf { ( a + b )}^{2} = 49 \\ \\ \sf a + b = +-7 \\ \\ \sf { ( a - b )}^{2} = {a}^{2} - 2ab + {b}^{2} \\ \\ \sf {(a - b)}^{2} = 41 - 8 \\ \\ \sf a - b = \sqrt{32}$

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