3(A2+ b2+c2)=(a+b+c)2
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Given a2+b2+c2+3=2(a+b+c) Expanding RHS we get a2+b2+c2+3=2a+2b+2c Carrying RHS to LHS -> a2+b2+c2+3-2a-2b-2c=0 We have a2-2a
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