Question

3. AABC - ADEF and their areas are respectively
100 cm2 and 49 cm2. If the altitude of AABC is 5 cm,
find the corresponding altitude of ADEF
BC TF BC​

Answer 1

ANSWER

STEP BY STEP EXPLANTION:

It is given that ∆ABC ~ ∆DEF.

Therefore, the ration of the areas of these triangles will be equal to the ratio of squares of their corresponding sides.

Also, the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding altitudes.

Let the altitude of ∆ABC be AP, drawn from A to BC to meet BC at P and the altitude of ∆DEF be DQ, drawn from D to meet EF at Q.

Then,

Hence, the altitude of ∆DEF is 3.5 cm