3) AABC is an equilateral triangle point P is on base BC such that
PC =½BC. If AB = 12cm. Find AP.
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Answer:
AP=3root 6
Step-by-step explanation:
Given =ABC is an equilateral triangle
AB =12
AB=AC=BC
PC =1/2 BC
Proof=
By pythogoras theorem
Hyp^2=base^2+perp^2
12^2=6^2+perp^2
perp^2=144-36
=108
Perpendicular =3root 6
Hence, AP=3root 6
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