Question

3-abc +abc 2 and -2abc +abc​

Answer 1

Answer:

ANSWER

30(a

2

bc+ab

2

c+abc

2

)

=2×3×5[(a×a×b×c)+(a×b×b×c)+(a×b×c×c)]

=2×3×5×a×b×c(a+b+c)

Thus 30(a

2

bc+ab

2

c+abc

2

)÷6abc

=

2×3×abc

2×3×5×abc(a+b+c)

=5(a+b+c)

Alternatively 30(a

2

bc+ab

2

c+abc

2

)÷6abc

=

6abc

30a

2

bc

+

6abc

30ab

2

c

+

6abc

30abc

2

=5a+5b+5c

=5(a+b+c)

Answer 2

Answer:

2 abc

Step-by-step explanation:

= (3+2-3) abc

=(5-3)abc

= 2abc