Question

3. ABC is an isosceles triangle in which altitudes
BE and CF are drawn to equal sides AC and AB
respectively (see Fig. 7.31). Show that these
altitudes are equal​

Answer 1

Answer: consider in bce and cbf

Ab=Ac [given]

<Abe=<Acf [each 90°]

to prove be =cf

we can take triangle Abe=Triangle Acf

<A=<A [common]

Ab=Ae[given]

in triangle Abe ≅triangle acf [aas congruence rule]

be =cf [cpct]

hence proved that these altitudes are equal

hope it helps you.