Question

3. ABC is an isosceles triangle in which altitudes
BE and CF are drawn to equal sides AC and AB
respectively (see Fig. 7.31). Show that these
altitudes are equal.
E
B
C​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

In △ABE and △ACF,

we have ∠BEA=∠CFA (Each 90

0

)

∠A=∠A (Common angle)

AB=AC (Given)

∴△ABE≅△ACF (By SAS congruence criteria)

∴BF=CF [C.S.C.T]