(3.) ABC is an isosceles triangle with AB=AC draw AP perpendicular BC to show that angle B=angle C
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An isosceles triangle is a triangle with (at least) two equal sides.
And in your question AB = AC
Then if we draw a perpendicular AD on BC then
Angle ADB = Angle ADC = 90°
So in both the triangle ADB and ADC three properties are same see,
Side AB = AC
Angle ADB = ADC
Side AD = AD
So it's proved that angle B = angle C
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