Question

3. ABC similar PQR such that ar (ABC)= 4 ar (PQR) if BC=12 cm then QR=
A) 6 cm
B) 8 cm
D) 10 cm

​

Answer 1

Answer:

ΔABC∼ΔPQR

ar(ΔABC)=4ar(ΔPQR)

area ΔPQR

area ΔABC

=

1

4

area(ΔPQR)

area(ΔABC)

=

QR

2

BC

2

1

4

=

QR

2

BC

2

⇒(

1

2

)

2

=(

QR

12

)

2

1

2

=

QR

12

⇒QR=

2

12×1

=6

QR=6cm