Question

3. ABCD is a parallelogram where ZB=80°, DT=10 cm, CT=7 cm and
2CDB=32°. Find m <BAD, M <ADB, AT and BD. Give reasons.​

Answer 1

Answer:

∠ADB+∠DBA+∠BAD=180  

o

             [ Sum of angles of triangle is 180  

o

 ]

⇒  40  

o

+30  

o

+∠BAD=180  

o

 

⇒  70  

o

+∠BAD=180  

o

 

⇒  ∠BAD=110  

o

 

⇒  ∠BAD=∠DCB=110  

o

                    [ Opposite angles of parallelogram are equal ]

⇒  ∠BAD+∠ADC=180  

o

              [ Adjacent angles of parallelogram ]

⇒  ∠BAD+∠ADB+∠BDC=180  

o

 

⇒  110  

o

+40  

o

+∠BDC=180  

o

 

⇒  ∠BDC=180  

o

−150  

o

 

⇒  ∠BDC=30  

o

 

∴   ∠ADC=40  

o

+30  

o

=70  

o

 

⇒  ∠ADC=∠ABC=70  

o

                 [ Opposite angles of parallelogram are equal ]

∴  ∠BAD=110  

o

,∠DCB=110  

o

,∠ADC=70  

o

 and ∠ABC=70  

o

 

∴∠BAD−∠DCB+∠ADC−∠ABC=100−100+70−70=0

mark me as the brainiest

Step-by-step explanation: