3.AD is an altitude of ABC in which AB=AC .show that AD bisects BC and A
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what do you mean I didn't understand
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Step-by-step explanation:
ANSWER
Given:-
ABC is an isosceles △.
AB=AC
AD is altitude.
∠ADB=∠ADC=90°
To prove:-
(i) AD bisects BC, i.e., BD=CD
(ii) AD bisects ∠A, i.e., ∠BAD=∠CAD
Proof:-
In △ADB and △ADC,
∠ADB=∠ADC[Each 90°]
AB=AC[Given]
AD=AD[Common]
By R.H.S congruency,
△ADB≅△ADC
By C.P.C.T.
BD=CD
∠BAC=∠CAD
Hence proved.
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