3. AM of 6, y, 7, x and 16 is a then
A) x + 2y = 1 B) x - y = 16
C) x + 2y = 0 D) x + y = 16
Answers
Answered by
1
Answer:
4
Step-by-step explanation:
xy(y−x)=16
xy
2
−x
2
y=16
y
2
−xy−
x
16
=0
(y−
2
x
)
2
−
4
x
2
−
x
16
=0
y=
2
x
±
4
x
2
+
x
16
y
′
=
2
1
±
2
1
(
4
x
2
+
x
16
4
2x
−
x
2
16
)
−1=±(
4
x
2
+
x
16
2
x
−
x
2
16
)
x
16
=
x
4
256
−
x
16
x
3
=8
x=2
& y=4
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