Question

3. Amit has a rectangular garden with sides 8 m
and 6 m. In the middle of the garden he left two
cross roads of Im width, in rest of the field he
put grass. If the cost of grassing is 50 per m
Find the total cost.
​

Answer 1

Given :

length of rectangleular garden = 8m

breadth of rectangular garden = 6m

width of cross roads = 1m

Solution :

Area of rectangular garden :

--> l × b

--> 8 × 6

--> 48m^2

Cross Roads 1 :

width = 1m

length = 8m

Area of cross road 1 = l × b

--> 1 × 8

--> 8m^2

Cross Road 2 :

width = 1m

Length = 6m

Area of cross road 2 = l × b

--> 1 × 6

--> 6m^2

Now we have to find the area of square formed by the intersecting of two cross roads

Square :

side = 1m

Area of square = side^2

--> 1^2

--> 1m^2

Area of the field with grass =

Area of rectangular garden - ( Area of cross road 1 + Area of cross road 2 - Area of square )

--> 48 - ( 8 + 6 - 1 )

--> 48 - 15

--> 33m ^2

Area of the field with grass = 33m^2

Cost of grassing :

Cost of grassing per m^2 = 50

Cost of grassing for 33m^2 = 50 × 33

--> Rs 1650

So total cost of grassing = Rs 1650

I hope it helps u dear friend !!^_^♡♡

Answer 2

Answer:

Tick the correct option

1 ) B

2) D

3) A

4) C

option sahi hai.....