Question

3. An ancient coin made of pure gold weighs 11.58g. Find its
volume when the density of gold is 19,300 kg/m^3.​

Answer 1

Step-by-step explanation:

Answer :-

Volume of the coin is 0.6 cm³ .

Explanation :-

We have :-

→ Weight of the coin = 11.58 g

→ Density of gold = 19300 kg/m³

To find:-

→ Volume of the coin.

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Firstly, let's convert the unit of density of gold from kg/m³ to g/cm³ .

⇒ 1 kg/m³ = 0.001 g/cm³

⇒ 19300 kg/m³ = 19300(0.001)

⇒ 19.3 g/cm³

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Volume = Weight/Density

Substituting values, we get :-

⇒ Volume = 11.58/19.3

⇒ Volume = 0.6 cm³

Answer 2

Given :

• → An ancient coin made of pure gold weighs 11.58g.
• → density of gold is 19,300 kg/m³

Need To Find :

• → Volume of coin ?

Formula Used Here :

• → Volume = Weight / Density

Conversion Needed :

• → 19300kg/m³ into g/m³
• → 19300 × 0.001
• → 19.3g/m³

According to Question :

• → Volume = Weight / Density
• → Volume = 11.58 / 19.3g/m³
• → Volume = 0.6cm3

Therefore :

• → The Volume of pure gold Coins is 0.6cm³

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