Question

3. An ancient coin made of pure gold weighs 11.58g. Find its
volume when the density of gold is 19,300 kg/m^3.

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Answer 1

Step-by-step explanation:

Answer :-

Volume of the coin is 0.6 cm³ .

Explanation :-

We have :-

→ Weight of the coin = 11.58 g

→ Density of gold = 19300 kg/m³

To find:-

→ Volume of the coin.

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Firstly, let's convert the unit of density of gold from kg/m³ to g/cm³ .

⇒ 1 kg/m³ = 0.001 g/cm³

⇒ 19300 kg/m³ = 19300(0.001)

⇒ 19.3 g/cm³

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Volume = Weight/Density

Substituting values, we get :-

⇒ Volume = 11.58/19.3

⇒ Volume = 0.6 cm³

Answer 2

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Volume of the coin is 0.6 cm^3

Step by step explanation:-

We have here

➩ Weight of the coin= 11.58g

➩ Density of Gold = 19300 kg/m^3

To Find:-

➩ Volume of the given coin

At first, let's convert the unit of density of the gold from kg/m^3 to g/cm^3

➩ 1 kg/m^3 = 0.001 g/cm^3

➩ 19300 kg/m^3 = 19300( 0.001)

➩ 19.3 g/cm^3

Now,

Volume formula = weight / Density

Substituting the values, in the formula we get :-

➩ Volume = 11.58 ÷ 19.3 = 0.6 cm^3 .

Hence the volume of the coin is 0.6 cm^3